A tank with a length 4m, width 2m and depth 3m is filled with a liquid of density
800kgm-3.What is the force acting on the bottom of the tankdue to that liquid pressure
The force acting on the bottom of the tank due to the liquid pressure can be calculated using the formula:
F = P x A
Where:
F is the force
P is the pressure
A is the area
To find the pressure, we use the formula:
P = ρgh
Where:
ρ is the density of the liquid
g is the acceleration due to gravity (approximately 9.8 m/s^2)
h is the height of the liquid column
Given:
ρ = 800 kg/m^3
g = 9.8 m/s^2
h = 3 m
Substituting these values into the formula, we can find the pressure:
P = 800 kg/m^3 x 9.8 m/s^2 x 3 m
P = 23,520 Pa
To find the area of the bottom of the tank, we use the formula:
A = length x width
Given:
length = 4 m
width = 2 m
Substituting these values into the formula, we can find the area:
A = 4 m x 2 m
A = 8 m^2
Now, we can calculate the force:
F = 23,520 Pa x 8 m^2
F = 188,160 N
Therefore, the force acting on the bottom of the tank due to the liquid pressure is 188,160 Newtons.