what mass of ethanol would be needed to produce 100 gram of ethyl ethanoate assuming the reaction went to completion
To find the mass of ethanol needed to produce 100 grams of ethyl ethanoate, we need to look at the balanced chemical equation for the reaction.
The chemical equation for the reaction between ethanol and ethanoic acid to form ethyl ethanoate and water is:
C2H5OH + CH3COOH → CH3COOC2H5 + H2O
From the balanced equation, we can see that the molar ratio between ethanol and ethyl ethanoate is 1:1.
Molar mass of ethanol (C2H5OH) = 12.01 g/mol (carbon) + 1.01 g/mol (hydrogen) + 16.00 g/mol (oxygen) = 46.07 g/mol
Therefore, 1 mole of ethanol (C2H5OH) has a mass of 46.07 grams.
Since the molar ratio between ethanol and ethyl ethanoate is 1:1, we can conclude that 100 grams of ethyl ethanoate will require the same mass of ethanol.
Therefore, the mass of ethanol needed to produce 100 grams of ethyl ethanoate is 100 grams.