A box has these letters inside it: B N T P N N T P B B N T. Which answer shows how to find the probability of drawing two Ns if the first letter is replaced before drawing the second?(1 point) Responses 48. 48 Start Fraction 4 over 8 End Fraction times Start Fraction 4 over 8 End Fraction 312.211 Start Fraction 3 over 12 End Fraction times Start Fraction 2 over 11 End Fraction 412.412 Start Fraction 4 over 12 End Fraction times Start Fraction 4 over 12 End Fraction 412+412
Which of the following is a list of the complete sample space for the compound event of rolling a number cube (1–6) and flipping a coin?(1 point) Responses 1H, 1T, 2H, 2T, 3H, 3T, 4H, 4T, 5H, 5T, 6H, 6T 1H, 1T, 2H, 2T, 3H, 3T, 4H, 4T, 5H, 5T, 6H, 6T 1H, 1T, 6H, 6T 1H, 1T, 6H, 6T 1H, 1T, 2H, 2T, 3H, 3T, 4H, 4T, 5H, 5T, 6H, 6T, H1, T1, H2, T2, H3, T3, H4, T4, H5, T5, H6, T6 1H, 1T, 2H, 2T, 3H, 3T, 4H, 4T, 5H, 5T, 6H, 6T, H1, T1, H2, T2, H3, T3, H4, T4, H5, T5, H6, T6 1H, 2H, 3H, 4H, 5H, 6H
The correct answer is: 1H, 1T, 2H, 2T, 3H, 3T, 4H, 4T, 5H, 5T, 6H, 6T.
This is because when rolling a number cube, you can get numbers 1-6. When flipping a coin, you can either get heads (H) or tails (T). To find the sample space for the compound event of rolling a number cube and flipping a coin, you need to list all possible outcomes by combining the outcomes of rolling the number cube with the outcomes of flipping the coin.
Which of the following situations is represented by the tree diagram? (1 point) Responses 3 sandwich choices, 3 side choices, 6 drink choices 3 sandwich choices, 3 side choices, 6 drink choices 1 sandwich choice, 3 side choices, 6 drink choices 1 sandwich choice, 3 side choices, 6 drink choices 3 sandwich choices, 9 side choices, 18 drink choices 3 sandwich choices, 9 side choices, 18 drink choices 3 sandwich choices, 3 side choices, 2 drink choices
Identify the event “greater than 9” if the sample space is {0, 1, 1, 2, 4, 5, 7, 9, 10, 11, 11, 12} .(1 point) Responses {9, 10, 11, 11, 12} left brace 9 comma 10 comma 11 comma 11 comma 12 right brace {10, 11, 12} left brace 10 comma 11 comma 12 right brace {10, 11, 11, 12} left brace 10 comma 11 comma 11 comma 12 right brace {0, 1, 1, 2, 4, 5, 7}
The correct answer is: {10, 11, 11, 12}
The event "greater than 9" includes all the numbers from the sample space that are greater than 9. In this case, the numbers that are greater than 9 are 10, 11, 11, and 12.
An experiment consists of rolling a 6-sided number cube then flipping a coin. How many total outcomes are in the sample space, and what outcomes would the event “even number and heads” consist of?(1 point) Responses There are 12 outcomes in the sample space. The event “even number and heads” includes {1H, 2H, 3H, 4H, 5H, 6H, 1T, 2T, 3T, 4T, 5T, 6T}. There are 12 outcomes in the sample space. The event “even number and heads” includes left brace 1 upper H comma 2 upper H comma 3 upper H comma 4 upper H comma 5 upper H comma 6 upper H comma 1 upper T comma 2 upper T comma 3 upper T comma 4 upper T comma 5 upper T comma 6 upper T right brace . There are 6 outcomes in the sample space. The event “even number and heads” includes {2H, 4H, 6H}. There are 6 outcomes in the sample space. The event “even number and heads” includes left brace 2 upper H comma 4 upper H comma 6 upper H right brace . There are 12 outcomes in the sample space. The event “even number and heads” includes {2H, 4H, 6H}. There are 12 outcomes in the sample space. The event “even number and heads” includes left brace 2 upper H comma 4 upper H comma 6 upper H right brace . There are 6 outcomes in the sample space. The event “even number and heads” includes {1H, 2H, 3H, 4H, 5H, 6H}.
Ingrid and Thomas both enter a raffle where they get a chance to pull one winning ticket from a box. If there are 25 tickets in the box and tickets are not replaced, what is the probability that both will pull a losing ticket from the box? Write your answer as a simplified fraction.(1 point)
The probability that Ingrid pulls a losing ticket is 24/25, since there are 24 losing tickets out of a total of 25.
Since the tickets are not replaced, after Ingrid pulls a ticket, there is now one less ticket in the box. Therefore, the probability that Thomas pulls a losing ticket is 23/24.
To find the probability that both Ingrid and Thomas pull a losing ticket, we multiply their individual probabilities:
(24/25) * (23/24) = 552/600
This can be simplified to 23/25.
So, the probability that both Ingrid and Thomas will pull a losing ticket is 23/25.
The correct answer is: Start Fraction 4 over 8 End Fraction times Start Fraction 4 over 8 End Fraction.
This is because there are 4 Ns in the box out of a total of 8 letters. When the first N is replaced, there are still 4 Ns in the box, but now out of a total of 8 letters (since the first letter was replaced). Thus, the probability of drawing two Ns is Start Fraction 4 over 8 End Fraction times Start Fraction 4 over 8 End Fraction.
The correct answer is: 3 sandwich choices, 3 side choices, 6 drink choices.
A tree diagram is typically used to represent a series of choices or events with multiple outcomes at each step. In this case, there are three sandwich choices, three side choices, and six drink choices, leading to multiple possible combinations of a sandwich, side, and drink.