What is the formula for finding the surface area of a regular triangular pyramid?(1 point) Responses SA=a2+2aa24+h2−−−−−−√ cap s cap A is equal to A squared plus 2 A square root of the fraction with numerator A squared and denominator 4 plus h squared end root SA=12ab+3(12lb) cap s cap A is equal to 1 half A b plus 3 times open paren 1 half pounds close paren SA=lw+12w4h2+l2−−−−−−−√+12l4h2+w2−−−−−−−√ cap s cap A is equal to l w plus 1 half w square root of 4 h squared plus l squared end root plus 1 half l square root of 4 h squared plus w squared end root SA=2(wl+lh+hw)
