In the chemical reaction, Calcium carbonate (CaCO3) was heated to form two new substances: Calcium oxide (CaO) and Carbon dioxide (CO2).
A student heated 24.8 g of CaCO3. After the reaction, they measured 13.9 g of CaO. What was the mass of the CO2 gas that escaped during the reaction?
Question 1 options:
24.8 g
38.7 g
1.78 g
10.9 g
To solve this problem, we need to determine the mass of CO2 produced by subtracting the mass of CaO formed from the starting mass of CaCO3.
Mass of CaCO3 = 24.8 g
Mass of CaO formed = 13.9 g
Mass of CO2 produced = Mass of CaCO3 - Mass of CaO formed
= 24.8 g - 13.9 g
= 10.9 g
Therefore, the mass of CO2 gas that escaped during the reaction is 10.9 g.
The correct answer is 10.9 g.