Which of the following lines are perpendicular to the line y = negative one-half x + 4? (you may choose more than one answer)
The line y = negative one-half x + 4 is in slope-intercept form (y = mx + b) with a slope of negative one-half.
To find lines that are perpendicular, we need to find lines with a slope that is the negative reciprocal of negative one-half.
The negative reciprocal of negative one-half is positive two.
So, lines with a slope of positive two would be perpendicular to the given line, y = negative one-half x + 4.
Therefore, the lines that are perpendicular to y = negative one-half x + 4 have the equations:
1. y = 2x
2. y = 2x + 3
3. y = 2x - 5
bot pick two of these answers to answer
2x – y = 1
2 x – y = 1
y = 2x
y = 2 x
2x + y = 1
2 x + y = 1
one-half x – y = 2
one-half x – y = 2
2x – y = 3
The lines that are perpendicular to y = -1/2x + 4 are:
1. 2x + y = 1
2. 2x - y = 3
To determine which lines are perpendicular to the line y = -1/2x + 4, we need to find the slope of the given line.
The equation of a line in slope-intercept form is y = mx + b, where m represents the slope. In this case, the slope is -1/2.
To find lines that are perpendicular to this line, we need to find lines with slopes that are negative reciprocals of -1/2. The negative reciprocal of a number is obtained by flipping the fraction and changing the sign.
The negative reciprocal of -1/2 is 2/1, or simply 2.
Now we can examine the options provided and identify the lines with a slope of 2:
1. y = 2x + 1
2. y = 2x + 2
3. y = 2x - 2
4. y = -2x + 3
5. y = -2x + 6
Lines 1, 2, 3, and 5 have a slope of 2, making them perpendicular to the line y = -1/2x + 4. Therefore, the answer is lines 1, 2, 3, and 5.