The table below show for examples of pairs of objects, the masses of each object in the pair, and the distances between the objects, in which example is a gravitational force of attraction between the two objects the greatest explain how you know this example one masses M one equals 102 equals 200 distance is 20 example 2 is M1 equals 102 equals 200 distance is 10 example 3 masses and one equals 50 and two equals 100 distance is 20 example for masses M1 equals 5 and two equals 100 distance is 10
To determine in which example the gravitational force of attraction between the two objects is the greatest, we need to calculate the force of attraction using Newton's law of universal gravitation:
F = (G * M1 * M2) / d^2
where F is the gravitational force of attraction, G is the gravitational constant, M1 and M2 are the masses of the objects, and d is the distance between the objects.
Example 1:
M1 = 200
M2 = 200
d = 20
F1 = (G * 200 * 200) / 20^2
Example 2:
M1 = 200
M2 = 200
d = 10
F2 = (G * 200 * 200) / 10^2
Example 3:
M1 = 50
M2 = 100
d = 20
F3 = (G * 50 * 100) / 20^2
Example 4:
M1 = 5
M2 = 100
d = 10
F4 = (G * 5 * 100) / 10^2
Comparing the force values:
F1 = (G * 200 * 200) / 400 = (G * 200 * 200) / 400 = G * 100
F2 = (G * 200 * 200) / 100 = 2 * F1
F3 = (G * 50 * 100) / 400 = (G * 50 * 100) / 400 = G * 12.5
F4 = (G * 5 * 100) / 100 = 5 * F3
From the calculations, we can see that F2 = 2 * F1, F3 = G * 12.5, and F4 = 5 * F3.
Therefore, in Example 2 where the distance is 10 units, the gravitational force of attraction is the greatest because it is twice the force value obtained in Example 1, four times the force value in Example 3, and ten times the force value in Example 4.