Find the surface area of a cylinder with a diameter of 12 in and height of 10 in use the approximation of 3.14 for pi
To find the surface area of a cylinder, we need to find the area of the two bases and the lateral surface area.
The formula for the area of a circle is A = πr^2, where r is the radius.
Given that the diameter is 12 inches, the radius is half of that, so the radius is 6 inches.
1. Base area:
A = πr^2
A = 3.14 * (6^2)
A = 3.14 * 36
A = 113.04 square inches
Since there are two bases, the total area of the bases is 2 * 113.04 = 226.08 square inches.
2. Lateral surface area:
The lateral surface area of a cylinder is described by the formula A = 2πrh, where r is the radius and h is the height.
A = 2 * 3.14 * 6 * 10
A = 376.8 square inches
3. Total surface area:
The total surface area is the sum of the base area and the lateral surface area.
Total surface area = base area + lateral surface area
Total surface area = 226.08 + 376.8
Total surface area = 602.88 square inches
Therefore, the surface area of the cylinder is approximately 602.88 square inches.