Two equations are written to express how far a car can go 60 miles when driving on different roads. On Road 1, the car can go 90 miles in 2 hours. On Road 2, the car can go g * in 4 hours. Write an equation where y is the distance in miles and ∞ is the time in hours to represent the motion of the faster car. (1 point)
The equation for the car driving on Road 1 is:
y = 90/2 = 45 miles per hour
The equation for the car driving on Road 2 is:
y = g/4 miles per hour
Since we want the equation to represent the motion of the faster car, the equation is:
y = ∞/t where t is the time in hours.
What
I apologize for the mistake in my previous response. Here is the correct equation:
The equation for the car driving on Road 1 is:
y = 90 miles/2 hours = 45 miles per hour
The equation for the car driving on Road 2 is:
y = g * (1/4) miles per hour
Since we want the equation to represent the motion of the faster car, we can set the two equations equal to each other:
45 = g * (1/4)
Simplifying the equation, we can multiply both sides by 4 to get rid of the fraction:
180 = g
Therefore, the equation representing the motion of the faster car is:
y = 180 * (1/4) miles per hour
Thats not the right answer
Apologies for the confusion. Let's try again.
The equation for the car driving on Road 1 is:
y = 90 miles/2 hours = 45 miles per hour
The equation for the car driving on Road 2 is:
y = g * (4/1) miles per hour (since the car can go g miles in 4 hours)
Since we want the equation to represent the motion of the faster car, we can set the two equations equal to each other:
45 = g * (4/1)
Simplifying the equation, we can multiply both sides by 1/4 to solve for g:
g = 45 * (1/4)
g = 45/4
Therefore, the equation representing the motion of the faster car is:
y = (45/4) * (4/1) miles per hour
y = 45 miles per hour
45 is not the answer
Apologies once again for the incorrect response. Let's correct it:
The equation for the car driving on Road 1 is:
y = 90 miles/2 hours = 45 miles per hour
The equation for the car driving on Road 2 is:
y = g * (1/4) miles per hour
Since we want the equation to represent the motion of the faster car, we can set the two equations equal to each other:
45 = g * (1/4)
To solve for g, we can multiply both sides of the equation by 4:
45 * 4 = g
g = 180
Therefore, the equation representing the motion of the faster car is:
y = 180 * (1/4) miles per hour
y = 45 miles per hour
So, the correct answer is 45 miles per hour. Thank you for bringing the mistake to my attention, and I apologize for any confusion caused.