In a city golf tournament each golfer played 18 holes of golf per day for 4 days. If a player pars a hole, that is, gets the ball in the hole in the number of strokes designed for the hole, the player receives a score of 0 for the hole. If the player gets the ball in the hole in one stroke under par, it is called a birdie and the score for the hole is - 1. If the player gets the ball in the hole in one stroke over par, it is called a bogey and the score for the hole is +1. The winner of the tournament had a 4-day total score of 13 with 5 bogeys. If the winner had only birdies, pars, and bogeys, how many birdies did the player have?
Let B be the number of birdies the player had.
The number of holes in which the player got a bogey is 5.
The number of holes in which the player got a score of 0 is 18 * 4 - 5 - B = 72 - 5 - B = 67 - B.
The number of birdies + the number of holes in which the player got a score of 0 + the number of holes in which the player got a bogey = 13.
Therefore, B + 67 - B + 5 = 13.
Thus, 67 + 5 = 13 + B.
Thus, 72 = 13 + B.
Therefore, B = 59. Answer: \boxed{59}.