The pair of points (6, y) and (10, –1) lie on a line with slope 1/4. What is the value of y?
Using the formula for slope,
$1/4 = \dfrac{y - (-1)}{6 - 10} = \dfrac{y + 1}{-4}.$
Therefore, $4y + 4 = -4$, so $4y = -8$, and $y = \boxed{-2}$.
$1/4 = \dfrac{y - (-1)}{6 - 10} = \dfrac{y + 1}{-4}.$
Therefore, $4y + 4 = -4$, so $4y = -8$, and $y = \boxed{-2}$.