identify all the zeros of the function y=3(x-2)(x+1)(x-4)
To find the zeros of the function y = 3(x - 2)(x + 1)(x - 4), we set y equal to zero and solve for x:
0 = 3(x - 2)(x + 1)(x - 4)
Setting each factor equal to zero gives us:
x - 2 = 0
x = 2
x + 1 = 0
x = -1
x - 4 = 0
x = 4
Therefore, the zeros of the function are x = 2, x = -1, and x = 4.