use the equation to answer the question.
ch4+2o2>co2+2h2o
if you change the 2 in front of 2o2 to a 3, what will be the change in the results on the right side of the equation?
a ) there is an extra o2 molecule left over.
b ) nothing changes in the equation.
c ) there are now 3h2o molecules.
d ) there are now 3c02 molecules.
The correct answer is a) there is an extra O2 molecule left over.
When you change the coefficient in front of O2 from 2 to 3, it means that there are now 3 O2 molecules reacting with CH4. However, on the right side of the equation, there is still only 2 CO2 and 2 H2O molecules produced. Therefore, there is an extra O2 molecule that is not being used in the reaction and is left over.