Which of the following is a point on the graph as described by the function y = (2z + 1) ^ 2 - 47 (1 point)
O (- 1, - 3)
O (1, 2)
O (- 1, - 5)
O (0, - 2)
To find the point on the graph, we need to substitute the given values of x and y into the equation.
Let's start with option O (-1, -3):
When x = -1, we have y = (2(-1) + 1)^2 - 47 = (-1)^2 - 47 = 1 - 47 = -46. Therefore, the point (-1, -3) does not satisfy the equation.
Now let's try option O (1, 2):
When x = 1, we have y = (2(1) + 1)^2 - 47 = (2 + 1)^2 - 47 = 3^2 - 47 = 9 - 47 = -38. Therefore, the point (1, 2) does not satisfy the equation.
Next, let's check option O (-1, -5):
When x = -1, we have y = (2(-1) + 1)^2 - 47 = (-2 + 1)^2 - 47 = (-1)^2 - 47 = 1 - 47 = -46. Therefore, the point (-1, -5) does not satisfy the equation.
Finally, let's try option O (0, -2):
When x = 0, we have y = (2(0) + 1)^2 - 47 = (0 + 1)^2 - 47 = 1^2 - 47 = 1 - 47 = -46. Therefore, the point (0, -2) does not satisfy the equation.
None of the given options satisfy the equation.