Which of the following is a point on the graph as described by the function y=(2x+1)2−4 ?(1 point)
To find a point on the graph described by the function \( y = (2x + 1)^2 - 4 \), we first need to choose a value for \( x \) and then calculate the corresponding \( y \)-value.
Let's choose \( x = 0 \) as it is typically the easiest value to start with:
1. Substitute \( x = 0 \) into the function:
\( y = (2(0) + 1)^2 - 4 \)
2. Simplify the expression inside the parentheses:
\( y = (0 + 1)^2 - 4 \)
3. Calculate the square:
\( y = 1^2 - 4 \)
4. Finally, solve for \( y \):
\( y = 1 - 4 \)
\( y = -3 \)
Therefore, the point (0, -3) is on the graph of the function \( y = (2x + 1)^2 - 4 \).