2/5 - y/y-2
a)-3y-2/y-2
b) -3y -2/5(4-2)
c) -3y-4/5(y-2)
d) -3y-4/y-2

The way you have written the problem, is 2/5 minus y^3. I don't think that is what you meant. Please use grouping symbols on fractions () or []

The way you have written the problem, is 2/5 minus y^3. I don't think that is what you meant. Please use grouping symbols on fractions () or []

it if a fraction 2/5 - y/(y-2)

common denominator: 5(y-2)

2y-4 -5y is the numerator (you need to combine)

I came up with -3y-4/5(y-2) is this correct?

## Yes, your answer is correct. To solve the subtraction problem, we need to find a common denominator for the fractions. In this case, the common denominator is 5(y-2).

Now, let's simplify the numerator. We have 2/5 - y/(y-2). To subtract these fractions, we need to find a common denominator, which is 5(y-2).

For the first fraction, 2/5, we can multiply the numerator and denominator by (y-2) to get 2(y-2)/(5(y-2)).

For the second fraction, y/(y-2), we can multiply the numerator and denominator by 5 to get 5y/(5(y-2)).

Now, we can combine the numerators and write the subtraction as a single fraction:
2(y-2)/(5(y-2)) - 5y/(5(y-2)).

Next, we can simplify the numerators by distributing the 2 and the 5:
(2y - 4)/(5(y-2)) - 5y/(5(y-2)).

To subtract these fractions, we need to have the same denominator, which we already have. Therefore, we can simply subtract the numerators and keep the denominator the same:
(2y - 4 - 5y)/(5(y-2)).

Combining like terms in the numerator, we get -3y - 4:
(-3y - 4)/(5(y-2)).

So, the expression 2/5 - y/(y-2) simplifies to (-3y - 4)/(5(y-2)), which matches option d) -3y-4/y-2.