A rental car company charges $33.27 per day to rent a car and $0.07 for every mile driven. Melanie wants to rent a car, knowing that:
She plans to drive 50 miles.
She has at most $120 to spend.
Which inequality can be used to determine dd, the maximum number of days Melanie can afford to rent for while staying within her budget?
33.27(d+3.5)≥120
33, point, 2, 7, d, plus, 3, point, 5, is greater than or equal to, 12033.27d+3.5≥120
33, point, 2, 7, d, plus, 3, point, 5, is less than or equal to, 12033.27d+3.5≤120
33, point, 2, 7, left bracket, d, plus, 3, point, 5, right bracket, is less than or equal to, 12033.27(d+3.5)≤120
To determine the maximum number of days, d, that Melanie can afford to rent the car while staying within her budget, we will set up an inequality equation that accounts for the daily rental fee and the cost per mile she drives.
The daily rental fee is $33.27 per day, and she plans to drive 50 miles, which will cost $0.07 per mile. The total cost for driving will therefore be 50 miles times $0.07 per mile.
Now, let's calculate that cost:
Cost for miles driven = 50 miles * $0.07/mile = $3.50
Now, we set up the inequality considering her total budget is at most $120:
Cost for days rented + Cost for miles driven ≤ Total budget
$33.27 * d + $3.50 ≤ $120
Here we have the inequality that will allow us to solve for d, which is the number of days Melanie can rent the car:
33.27d + 3.5 ≤ 120
Therefore, the correct inequality is:
33.27d + 3.5 ≤ 120