A net force of 0.7 N is applied on a body. What happens to the acceleration of the body in a second trial if half of the net force is applied?
The acceleration remains the same. The acceleration remains the same. The acceleration is half of its original value. The acceleration is half of its original value. The acceleration is the square of its original value. The acceleration is the square of its original value. The acceleration is double its original value.
To determine what happens to the acceleration of the body in the second trial when only half of the net force is applied, we can use Newton's second law of motion:
F = ma
where F is the net force, m is the mass of the body, and a is the acceleration.
In the first trial, a net force of 0.7 N is applied. Let's assume the mass of the body remains constant for both trials.
In the second trial, only half of the net force is applied. Therefore, the net force in the second trial would be 0.7 N divided by 2, which is equal to 0.35 N.
Since mass remains constant, we can rearrange Newton's second law to solve for acceleration:
a = F/m
For the first trial, with a net force of 0.7 N:
a1 = 0.7 N / m
For the second trial, with a net force of 0.35 N (half of the original):
a2 = 0.35 N / m
Comparing the two accelerations:
a2/a1 = (0.35 N / m) / (0.7 N / m) = 0.5
Therefore, the acceleration in the second trial is half of its original value.
Hence, the correct answer is: The acceleration is half of its original value.