# A passenger train can travel 325 mi in the same time a freight train takes to travel 200 mi. If the speed of the passenger train is 25 mi/h faster than the speed of the freight train, find the speed of each.

Speed = distance/time

Therefore time = distance/speed. Assume the times are equal.

Let x stand for speed of freight train and x+25 speed of freight train. Therefore, with the same time,

325/(x+25) = 200/x

Solve for x.

I hope this helps. Thanks for asking.

## To find the speeds of the passenger train and freight train, we can use the formula for speed: speed = distance / time.

Let's assume the speed of the freight train is x miles per hour. Since the passenger train is 25 miles per hour faster, its speed would be x + 25 miles per hour.

We know that the passenger train can travel 325 miles in the same time it takes for the freight train to travel 200 miles. Therefore, the time taken by both trains is the same.

For the passenger train:
speed = distance / time
x + 25 = 325 / t

For the freight train:
speed = distance / time
x = 200 / t

Since the times are the same for both trains, we can set the equations equal to each other and solve for x:

x + 25 = x = 325 / 200

Simplifying the equation:
x + 25 = 1.625x

Subtracting x from both sides:
25 = 0.625x

Dividing both sides by 0.625:
x = 40

Therefore, the speed of the freight train is 40 miles per hour, and the speed of the passenger train is 40 + 25 = 65 miles per hour.