Zn(s) ǀ Zn2+(aq) ǀǀ Cu2+(aq) ǀ Cu(s), what is the number of moles of electrons for this
The given cell notation represents a redox reaction where zinc (Zn) solid is oxidized to form zinc ions (Zn2+) in the solution, while copper ions (Cu2+) in the solution are reduced to form solid copper (Cu).
The overall balanced equation for the redox reaction can be written as:
Zn(s) + Cu2+(aq) -> Zn2+(aq) + Cu(s)
In this reaction, Zn loses 2 electrons to form Zn2+ ions, and Cu2+ ions gain 2 electrons to form solid Cu. Thus, for every Zn atom, 2 moles of electrons are involved.
Therefore, the number of moles of electrons involved in this reaction is 2 moles of electrons.