A shortstop is standing in the base path between second and third base when she fields the ball. She is 25 feet from second base and needs to throw to first base. Assuming the field is square how far does she need to throw the ball
If the shortstop is standing in the base path between second and third base, and she needs to throw the ball to first base, she would need to throw the ball across the diagonal of the square field.
Using the Pythagorean theorem, we can determine the length of the diagonal (d) of the square field:
d^2 = 25^2 + 25^2
d^2 = 625 + 625
d^2 = 1250
Taking the square root of both sides, we find:
d ≈ √1250
d ≈ 35.36 feet
Therefore, the shortstop needs to throw the ball approximately 35.36 feet to first base.