What is the irrational cube root ^3√40 rewritten as a product of an integer and another irrational cube root
The irrational cube root ^3√40 can be rewritten as a product of an integer and another irrational cube root by finding a perfect cube that is a factor of 40.
The prime factorization of 40 is 2^3 * 5. Since there is one factor of 2^3, which is a perfect cube, we can rewrite ^3√40 as ^3√(8 * 5).
Taking the cube root of 8 gives ∛8 = 2. Therefore, we can rewrite ^3√40 as 2 * ^3√5.
So, ^3√40 can be rewritten as the product of the integer 2 and the irrational cube root ^3√5.