is f(x)=x^5+x^3 odd even or neither
To determine if the function f(x)=x^5+x^3 is odd, even, or neither, we need to test for symmetry.
1. Odd function: A function f(x) is odd if f(-x) = -f(x) for all x in the domain.
Let's test this for f(x)=x^5+x^3:
f(-x) = (-x)^5 + (-x)^3 = -x^5 - x^3
-f(x) = -(x^5 + x^3) = -x^5 - x^3
Since f(-x) = -f(x), the function f(x)=x^5+x^3 is odd.
Therefore, the function f(x)=x^5+x^3 is odd.