Use the image to answer the question.
A coordinate plane has an x-axis and y-axis both ranging from negative 7 to 7 in increments of 1. Points labeled with names of apples are plotted. Quadrant 1 is labeled with left parenthesis positive sign comma positive sign right parenthesis. Gala is plotted in quadrant 1. Gala is shown at 4 increments on the x-axis and 5 increments on the y-axis. Quadrant 2 is labeled with left parenthesis negative sign comma positive sign right parenthesis. Fuji is plotted in quadrant 2. Fuji is shown at 3 increments on the x-axis and 2 increments on the y-axis. Quadrant 3 is labeled with left parenthesis negative sign comma negative sign right parenthesis. Granny Smith is plotted in Quadrant 3. Granny Smith is shown at 4 increments on the x-axis and 4 increments on the y-axis. Quadrant 4 is labeled with left parenthesis positive sign comma negative sign right parenthesis. Pink Lady is plotted in quadrant 4. Pink Lady is shown at 3 increments on the x-axis and 3 increments on the y-axis.
Terrence is visiting an apple farm to pick apples. Use the graph to help him locate the Gala apples.
(1 point)
Responses
(−4, −5)
left parenthesis negative 4 comma negative 5 right parenthesis
(−4, 5)
left parenthesis negative 4 comma 5 right parenthesis
(4, 5)
left parenthesis 4 comma 5 right parenthesis
(5, 4)
The correct answer is: (4, 5) or left parenthesis 4 comma 5 right parenthesis.
Use the image to answer the question.
A coordinate plane shows four quadrants with words plotted in each quadrant. The x-axis and y-axis range from negative 7 to 7 in increments of 1. Quadrant 1 is labeled with left parenthesis positive sign comma positive sign right parenthesis. The label sharks is plotted in quadrant 1. Sharks is shown at 3 increments on the x-axis and 3 increments on the y-axis. Quadrant 2 is labeled with left parenthesis negative sign comma positive sign right parenthesis. The labels otters and turtles are plotted in quadrant 2. Otters is shown at 4 increments on the x-axis and 4 increments on the y-axis. Turtles is shown at 3 increments on the x-axis and 2 increments on the y-axis. Quadrant 3 is labeled with left parenthesis negative sign comma negative sign right parenthesis. Coral reef is plotted in quadrant 3. Coral reef is shown at 4 increments on the x-axis and 5 increments on the y-axis. Quadrant 4 is labeled with left parenthesis positive sign comma negative sign right parenthesis. The labels touch tank and penguins are plotted in quadrant 4. Touch tank is shown at 5 increments on the x-axis and 3 increments on the y-axis. Penguins is shown at 2 increments on the x-axis and 5 increments on the y-axis.
If someone visits the aquarium at the point (−3, 2), what will they find?
(1 point)
Responses
otters
otters
turtles
turtles
coral reef
coral reef
penguins
If someone visits the aquarium at the point (-3, 2), they will find otters.
Solve the following problem:
What is the distance from (−13, 12) to (−13, −77)?
(1 point)
Responses
−89
negative 89
89
89
65
65
26
To find the distance between two points on a coordinate plane, we can use the formula:
distance = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, the two points are (-13, 12) and (-13, -77). Plugging in the values into the formula:
distance = √((-13 - (-13))^2 + (-77 - 12)^2)
distance = √(0^2 + (-89)^2)
distance = √(0 + 7921)
distance = √7921
distance = 89
Therefore, the distance from (-13, 12) to (-13, -77) is 89.
Which of the following points has a distance of 10 from the point (−1, 2)?(1 point)
Responses
(−1, 10)
Left Parenthesis negative 1 comma 10 Right Parenthesis
(−1, −12)
Left Parenthesis negative 1 comma negative 12 Right Parenthesis
(−11, 2)
Left Parenthesis negative 11 comma 2 Right Parenthesis
(10, 2)
To find the point that has a distance of 10 from (-1, 2), we can calculate the distance between (-1, 2) and each of the given points using the distance formula:
distance = √((x2 - x1)^2 + (y2 - y1)^2)
Let's calculate the distances:
For (-1, 10):
distance = √((-1 - (-1))^2 + (10 - 2)^2) = √(0 + 64) = √64 = 8
For (-1, -12):
distance = √((-1 - (-1))^2 + (-12 - 2)^2) = √(0 + 196) = √196 = 14
For (-11, 2):
distance = √((-11 - (-1))^2 + (2 - 2)^2) = √((-10)^2 + 0^2) = √(100 + 0) = √100 = 10
For (10, 2):
distance = √((10 - (-1))^2 + (2 - 2)^2) = √((11)^2 + 0^2) = √(121 + 0) = √121 = 11
Therefore, the point (-11, 2) has a distance of 10 from (-1, 2).