MATH UNIT 5 LESSON 10 NEED HELP!!
Of course! I'd be happy to help you with any questions you have on Math Unit 5 Lesson 10. Just let me know what specific concept or problem you need assistance with, and I'll do my best to explain it to you.
a line that contains the point (0, -8) with a slope of 32 a line that contains the y-intercept (0, -2) and a slope of −34 a line that has a slope of 53 and a y-intercept of -4. a line that contains the points (0, -2) and (4, 0).
To find an equation of a line, we can use either the slope-intercept form (y = mx + b) or the point-slope form (y - y1 = m(x - x1)).
1. Line with a point (0, -8) and a slope of 32:
Using the point-slope form, the equation can be written as: y - (-8) = 32(x - 0)
Simplifying, we get: y + 8 = 32x
2. Line with a y-intercept of (0, -2) and a slope of -34:
Using the slope-intercept form, the equation can be written as: y = -34x - 2
3. Line with a slope of 53 and a y-intercept of -4:
Using the slope-intercept form, the equation can be written as: y = 53x - 4
4. Line containing the points (0, -2) and (4, 0):
First, find the slope using the formula m = (y2 - y1) / (x2 - x1).
Using (0, -2) and (4, 0), we have m = (0 - (-2)) / (4 - 0) = 2 / 4 = 1/2.
Next, we can use the point-slope form: y - (-2) = (1/2)(x - 0)
Simplifying, we get: y + 2 = (1/2)x
These are the equations of the lines based on the given information.
I put the wrong numbers here are the right ones. a line that contains the point (0, -8) with a slope of 3/2 a line that contains the y-intercept (0, -2) and a slope of −3/4 a line that has a slope of 5/
3 and a y-intercept of -4. a line that contains the points (0, -2) and (4, 0).
No problem! Let's find the equations of the lines based on the corrected information:
1. Line with a point (0, -8) and a slope of 3/2:
Using the point-slope form, the equation can be written as: y - (-8) = (3/2)(x - 0)
Simplifying, we get: y + 8 = (3/2)x
2. Line with a y-intercept of (0, -2) and a slope of -3/4:
Using the slope-intercept form, the equation can be written as: y = (-3/4)x - 2
3. Line with a slope of 5/3 and a y-intercept of -4:
Using the slope-intercept form, the equation can be written as: y = (5/3)x - 4
4. Line containing the points (0, -2) and (4, 0):
First, find the slope using the formula m = (y2 - y1) / (x2 - x1).
Using (0, -2) and (4, 0), we have m = (0 - (-2)) / (4 - 0) = 2 / 4 = 1/2.
Next, we can use the point-slope form: y - (-2) = (1/2)(x - 0)
Simplifying, we get: y + 2 = (1/2)x
These are the correct equations of the lines based on the given information. Let me know if there's anything else I can help you with!