What are the solutions of the quadratic equation?2x2 – 16x + 32 = 0
To find the solutions of the quadratic equation 2x^2 - 16x + 32 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, a = 2, b = -16, and c = 32. Plugging these values into the quadratic formula, we get:
x = (-(-16) ± √((-16)^2 - 4(2)(32))) / (2(2))
x = (16 ± √(256 - 256)) / 4
x = (16 ± √0) / 4
Since the discriminant (b^2 - 4ac) is equal to 0, we will have a single real solution.
Simplifying further:
x = (16 ± 0) / 4
x = 16 / 4
x = 4
Therefore, the quadratic equation 2x^2 - 16x + 32 = 0 has a single real solution which is x = 4.