Suppose that an object is dropped from a height of h meters and hits the ground with a velocity of v meters per second. Then v= √19.6h. If an object hits the ground with a velocity of 20.4 meters per second, from what height was it dropped?
To find the height from which the object was dropped, we need to rearrange the given equation v= √19.6h to solve for h. Squaring both sides of the equation, we have:
v^2 = 19.6h.
Substituting the value of v as 20.4 meters per second, we have:
(20.4)^2 = 19.6h.
Simplifying, we get:
h = (20.4)^2 / 19.6 = 20.8.
Therefore, the object was dropped from a height of 20.8 meters.