Plot the point 2,6
. What section is it in?
A first quadrant coordinate plane from 0 to 7 on the x and y axis is divided into 4 equal parts by 2 diagonal lines forming 4 triangles. The first diagonal line goes from 0 comma 0 to 7 comma 7. The second diagonal line goes from 0 comma 7 to 7 comma 0. * Part A is above both diagonal lines forming a triangle on the top. * Part B is below the first diagonal and above the second diagonal forming a triangle on the right. * Part C is below both diagonal lines forming a triangle on the bottom. * Part D is above the first diagonal and below the second diagonal forming a triangle on the left.
To determine the section where the point (2, 6) is located on the coordinate plane, we need to compare the x-coordinate (2) and the y-coordinate (6) with the equations of the diagonal lines that divide the plane.
The first diagonal line, which goes from (0, 0) to (7, 7), can be represented by the equation y = x.
The second diagonal line, which goes from (0, 7) to (7, 0), can be represented by the equation y = -x + 7.
Now, let's check the position of the point (2, 6) relative to these lines:
For the first line (y = x), since the y-coordinate (6) is greater than the x-coordinate (2), the point is above the line.
For the second line (y = -x + 7), the y-coordinate (6) is also greater than the x-coordinate (2), so the point is above this line as well.
Therefore, the point (2, 6) is located in Part A, which is above both diagonal lines, forming a triangle on the top.