What is the irrational cube root 3^√81 rewritten as a product of an integer and another irrational cube root?
To rewrite the cube root of 81 as a product of an integer and another irrational cube root, we can use the property of exponents that states √(a^b) = a^(b/2).
The cube root of 81 can be written as (81^(1/3))^(1/2) = 81^(1/6).
Therefore, the irrational cube root 3^√81 can be rewritten as 3^(81^(1/6)).