To find the point on the graph described by the function, we need to substitute the x-value and y-value into the function and see if it is true.
Let's check each option:
A. (0,−2): Substitute x = 0 into the function: y = (2(0) + 1)^2 - 4 = 1^2 - 4 = 1 - 4 = -3. The y-value is not -2, so this point is not on the graph.
B. (−1,−5): Substitute x = -1 into the function: y = (2(-1) + 1)^2 - 4 = (-2 + 1)^2 - 4 = (-1)^2 - 4 = 1 - 4 = -3. The y-value is not -5, so this point is not on the graph.
C. (−1,−3): Substitute x = -1 into the function: y = (2(-1) + 1)^2 - 4 = (-2 + 1)^2 - 4 = (-1)^2 - 4 = 1 - 4 = -3. The y-value is -3, so this point is on the graph.
D. (1,2): Substitute x = 1 into the function: y = (2(1) + 1)^2 - 4 = (2 + 1)^2 - 4 = 3^2 - 4 = 9 - 4 = 5. The y-value is not 2, so this point is not on the graph.
Therefore, the point on the graph described by the function is (−1,−3), which is option C.