(1,5), (2,10). On the graph what would be the equation of the line y=MX through the origin?
To find the equation of the line passing through the origin (0,0) and the point (1,5), we can use the slope-intercept form of a linear equation, y = mx + b, where m is the slope of the line and b is the y-intercept.
To find the slope, we can use the formula m = (y2 - y1)/(x2 - x1), where (x1, y1) = (0,0) and (x2, y2) = (1,5).
m = (5 - 0)/(1 - 0)
m = 5/1
m = 5
Therefore, the slope of the line passing through the origin and (1,5) is 5.
Now, we can substitute the slope into the equation y = mx + b and solve for b using the point (1,5):
5 = 5(1) + b
5 = 5 + b
b = 5 - 5
b = 0
Therefore, the y-intercept of the line passing through the origin and (1,5) is 0.
The equation of the line y = MX through the origin would be y = 5x.