which equation of a line that passes through (-10, 3) and is perpendicular to y=5y-7
The slope-intercept form of a line is given by y = mx + b, where m represents the slope and b represents the y-intercept.
The equation of the line y = 5x - 7 is already in slope-intercept form. The slope of this line is 5.
Since the line we want to find is perpendicular to y = 5x - 7, its slope is the negative reciprocal of 5. The negative reciprocal of 5 is -1/5. Therefore, the slope of the line we want to find is -1/5.
Using the point-slope form of a line, which is y - y1 = m(x - x1), where (x1, y1) is a point on the line, we can substitute the given point (-10, 3) and the slope -1/5 into the equation:
y - 3 = (-1/5)(x - (-10))
Simplifying:
y - 3 = (-1/5)(x + 10)
Distributing -1/5:
y - 3 = (-1/5)x - 2
Adding 3 to both sides:
y = (-1/5)x + 1