Tickets to the baseball game are on sale for $1.50 off the regular price. Dea buys 6 tickets. If her total cost is $51, how much is the regular price of each ticket? (1 point)
Let x be the regular price of each ticket.
The discounted price of each ticket is x - $1.50.
Dea's total cost is 6 * (x - $1.50) = $51.
So, 6x - $9 = $51
6x = $60
The regular price of each ticket is x = $<<10=10>>10. Answer: \boxed{10}.
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Certainly! Let's solve the problem again.
Let's assume the regular price of each ticket is x dollars.
Since each ticket is on sale for $1.50 off the regular price, the discounted price of each ticket is x - $1.50.
Dea buys 6 tickets, so her total cost is 6 * (x - $1.50).
According to the problem, her total cost is $51.
Therefore, we can write the equation as:
6 * (x - $1.50) = $51.
Now, let's solve for x:
6x - 9 = 51,
6x = 60,
x = 10.
Hence, the regular price of each ticket is $10.
To find the regular price of each ticket, we need to first determine the discounted price of each ticket.
Let's assume the regular price of each ticket is "x" dollars. Since Dea buys 6 tickets, her total cost would be 6 times the regular price.
So the equation becomes: 6x = $51.
To find the value of "x," we need to isolate it. To do this, we divide both sides of the equation by 6:
(6x)/6 = $51/6.
Simplifying, we get: x = $8.50.
Therefore, the regular price of each ticket is $8.50.