A student needs to create a simple series circuit using it 12 V battery, one lightbulb, and one resistor. The wire resistance is tiny. And one or two sentences, explain how the student could use ohms law to create a circuit with these conditions that has a current of 2.40 a
The student can use Ohm's Law (I = V/R) to calculate the resistance needed for a current of 2.40 A by rearranging the formula to solve for resistance (R = V/I). By plugging in the given values (V = 12 V, I = 2.40 A), the student can calculate the required resistance, which is 5 ohms. The student can then connect the lightbulb and resistor in series to achieve the desired current.
