Which of the following is a point on the graph as described by the function y=(2x+1)^2−4 ?
(1,2)
(0,−2)
(−1,−5)
(−1,−3)
To find the points on the graph of the function y=(2x+1)^2−4, we substitute the given x-values into the equation and calculate the corresponding y-values.
For the point (1,2), plugging in x = 1:
y = (2(1)+1)^2−4
y = (2+1)^2−4
y = 3^2−4
y = 9−4
y = 5
So the point (1,2) is not on the graph of the function.
For the point (0,-2), plugging in x = 0:
y = (2(0)+1)^2−4
y = (0+1)^2−4
y = 1^2−4
y = 1−4
y = -3
So the point (0,-2) is not on the graph of the function.
For the point (-1,-5), plugging in x = -1:
y = (2(-1)+1)^2−4
y = (-2+1)^2−4
y = (-1)^2−4
y = 1−4
y = -3
So the point (-1,-5) is not on the graph of the function.
For the point (-1,-3), plugging in x = -1:
y = (2(-1)+1)^2−4
y = (-2+1)^2−4
y = (-1)^2−4
y = 1−4
y = -3
So the point (-1,-3) is on the graph of the function.