Use the image to answer the question.
An illustration of a coordinate plane with four quadrants shows the x-axis ranging from negative 9 to 9 and the y-axis ranging from negative 11 to 11 in increments of 1. A solid upward line with arrows on both ends is plotted on the graph. The line passes through the plotted points left parenthesis 0 comma negative 2 right parenthesis and left parenthesis 3 comma 0 right parenthesis.
Write the equation of the line in slope-intercept form.
(1 point)
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To find the equation of the line in slope-intercept form, we need to determine the slope (m) and the y-intercept (b) of the line.
To find the slope, we can use the formula:
m = (y2 - y1) / (x2 - x1)
The points given are (0, -2) and (3, 0). Plugging these values into the formula, we get:
m = (0 - (-2)) / (3 - 0)
m = 2 / 3
Now that we have the slope (m), we can find the y-intercept (b) using the point-slope formula:
y = mx + b
Plugging in the values of the slope and one of the points (0, -2), we get:
-2 = (2/3)(0) + b
-2 = 0 + b
b = -2
Therefore, the equation of the line in slope-intercept form is:
y = (2/3)x - 2