the remainder of
(x^3-4x^2+6x-4) / (x-2)
Using polynomial long division:
x^2 - 2x + 2
----------------------
x - 2 | x^3 - 4x^2 + 6x - 4
- (x^3 - 2x^2)
--------------
-2x^2 + 6x
- (-2x^2 + 4x)
---------------
2x - 4
- (2x - 4)
----------
0
Therefore, the remainder of (x^3 - 4x^2 + 6x - 4) divided by (x - 2) is 0.