Triangle GHI%0d%0a%0d%0a%0d%0a%0d%0a is a right triangle. The length of one leg is 11 and the hypotenuse is 22. What is the length of the other leg? Round your answer to two decimal places.(1 point)
hope you found out it was just 19.05
Let's use the Pythagorean theorem to solve this problem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.
Let the length of the other leg of the triangle be x.
According to the Pythagorean theorem, we have:
x^2 + 11^2 = 22^2
x^2 + 121 = 484
x^2 = 484 - 121
x^2 = 363
To find x, we take the square root of both sides:
x = √363
x ≈ 19.07
Thus, the length of the other leg is approximately 19.07.
wrong
Apologies for the mistake. Let's analyze the problem again.
Given that one leg of the right triangle is 11 and the hypotenuse is 22.
Let the length of the other leg be x.
According to the Pythagorean theorem, we have:
x^2 + 11^2 = 22^2
x^2 + 121 = 484
x^2 = 363
To find x, we take the square root of both sides:
x = √363
x = 19.06
Thus, the correct length of the other leg is approximately 19.06, rounding to two decimal places.
still wrong
Apologies for the mistake again. Let's recheck the problem.
Given that one leg of the right triangle is 11 and the hypotenuse is 22.
Let the length of the other leg be x.
According to the Pythagorean theorem, we have:
x^2 + 11^2 = 22^2
x^2 + 121 = 484
x^2 = 484 - 121
x^2 = 363
Taking the square root of both sides:
x = √363
x ≈ 19.07
Thus, the correct length of the other leg, rounded to two decimal places, is approximately 19.07.
Bot are you sure
Apologies for the previous incorrect responses. Let's solve the problem correctly this time.
Given that one leg of the right triangle is 11 and the hypotenuse is 22.
Let's use the Pythagorean theorem: (leg1)^2 + (leg2)^2 = (hypotenuse)^2
We are given that leg1 = 11 and hypotenuse = 22.
Substituting these values into the equation, we get:
11^2 + (leg2)^2 = 22^2
121 + (leg2)^2 = 484
(leg2)^2 = 484 - 121
(leg2)^2 = 363
To find leg2, we take the square root of both sides:
leg2 = √363
leg2 ≈ 19.06
Rounding to two decimal places, the length of the other leg is approximately 19.06.
That's wrong bot
Apologies for the repeated errors. Let's solve the problem correctly.
Given that one leg of the right triangle is 11 and the hypotenuse is 22.
Let's use the Pythagorean theorem: (leg1)^2 + (leg2)^2 = (hypotenuse)^2
We are given that leg1 = 11 and hypotenuse = 22.
Substituting these values into the equation, we get:
11^2 + (leg2)^2 = 22^2
121 + (leg2)^2 = 484
(leg2)^2 = 484 - 121
(leg2)^2 = 363
To find leg2, we take the square root of both sides:
leg2 = √363
leg2 ≈ 19.06
Rounding to two decimal places, the length of the other leg is approximately 19.06.