Bill and Amy want to ride their bikes from their neighborhood to school which is 14.4 kilometers away. It takes Amy 40 minutes to arrive at school. Bill arrives 20 minutes after Amy. How much faster (in meters/second)is Amy's average speed for the entire trip?
First, let's convert the time it takes Amy to arrive at school in minutes to hours: 40 minutes * 1 hour/60 minutes = 2/3 hours
Then, let's convert the distance from kilometers to meters: 14.4 kilometers * 1000 meters/kilometer = <<14.4*1000=14400>>14400 meters
Now let's calculate Amy's average speed in meters/second: 14400 meters / (2/3 hours * 3600 seconds/hour) = 6 meters/second
Bill arrives 20 minutes later, so his time for the entire trip is 2/3 hours + 20 minutes * 1 hour/60 minutes = 2/3 hours + 1/3 hours = 1 hour
Bill's average speed for the trip is 14400 meters / 1 hour * 3600 seconds/hour = <<14400=14400>>14400 meters/hour= <<14400/3600=4>>4 meters/second
Thus, Amy's average speed for the entire trip is 6 meters/second - 4 meters/second = <<6-4=2>>2 meters/second faster. Answer: \boxed{2}.