Which of the following points is a solution to the linear inequality  y>19x−29 ?

(0,−19) left parenthesis 0 comma negative Start Fraction 1 over 9 End Fraction right parenthesis (0,−29) left parenthesis 0 comma negative Start Fraction 2 over 9 End Fraction right parenthesis (0,−49) left parenthesis 0 comma negative Start Fraction 4 over 9 End Fraction right parenthesis (0,−13)

To determine which point is a solution to the linear inequality y > 19x - 29, we substitute the x and y values of each point into the inequality and see if the resulting inequality holds true.

1) (0,-19):
-19 > 19(0) - 29
-19 > -29
This is true, so (0,-19) is a solution.

2) (0, 1/9):
1/9 > 19(0) - 29
1/9 > -29
This is true, so (0, 1/9) is a solution.

3) (0, -29):
-29 > 19(0) - 29
-29 > -29
This is NOT true, so (0, -29) is not a solution.

4) (0, 2/9):
2/9 > 19(0) - 29
2/9 > -29
This is true, so (0, 2/9) is a solution.

5) (0, -49):
-49 > 19(0) - 29
-49 > -29
This is NOT true, so (0, -49) is not a solution.

6) (0, -13):
-13 > 19(0) - 29
-13 > -29
This is true, so (0, -13) is a solution.

From the given points, the solutions to the linear inequality y > 19x - 29 are (0, -19), (0, 1/9), (0, 2/9), and (0, -13).

Pick one option

One option is (0, -19)

That is not an option

Apologies for the confusion. The correct option from the given points that is a solution to the linear inequality y > 19x - 29 is (0, -13).

Which of the following points is a solution to the linear inequality y>1/9x−2/9 ?

(0,−1/9) left parenthesis 0 comma negative Start Fraction 1 over 9 End Fraction right parenthesis (0,−2/9) left parenthesis 0 comma negative Start Fraction 2 over 9 End Fraction right parenthesis (0,−4/9) left parenthesis 0 comma negative Start Fraction 4 over 9 End Fraction right parenthesis (0,−1/3)

To determine which point is a solution to the linear inequality y > (1/9)x - (2/9), we substitute the x and y values of each point into the inequality and check if the resulting inequality holds true.

1) (0, -1/9):
-1/9 > (1/9)(0) - (2/9)
-1/9 > -2/9
This is true, so (0, -1/9) is a solution.

2) (0, -2/9):
-2/9 > (1/9)(0) - (2/9)
-2/9 > -2/9
This is NOT true, so (0, -2/9) is not a solution.

3) (0, -4/9):
-4/9 > (1/9)(0) - (2/9)
-4/9 > -2/9
This is NOT true, so (0, -4/9) is not a solution.

4) (0, -1/3):
-1/3 > (1/9)(0) - (2/9)
-1/3 > -2/9
This is true, so (0, -1/3) is a solution.

From the given points, the solutions to the linear inequality y > (1/9)x - (2/9) are (0, -1/9) and (0, -1/3).

Is the point  (0,−3)  a solution to the inequality  y>4/5x−3 , as shown on the graph?

Yes, because (0,−3) falls within the shaded region. Yes, because  left parenthesis 0 comma negative 3 right parenthesis  falls within the shaded region. No, because (0,−3) falls within the shaded region. No, because  left parenthesis 0 comma negative 3 right parenthesis  falls within the shaded region. Yes, because (0,−3) falls on the boundary line. Yes, because  left parenthesis 0 comma negative 3 right parenthesis  falls on the boundary line. No, because (0,−3) falls on the boundary line. No, because  left parenthesis 0 comma negative 3 right parenthesis  falls on the boundary line.

No, because (0, -3) falls on the boundary line.

Show which of the following points is part of the solution set for the inequality  y≤2/5x+1 .

(10,5.5) left parenthesis 10 comma 5.5 right parenthesis (−10,6) left parenthesis negative 10 comma 6 right parenthesis (10,6) left parenthesis 10 comma 6 right parenthesis (10,4)