An average American household uses about 1.04 x 104 kWh (kilowatt hours) of electricity a vear. If a power

station generates 2.496 × 1010 kWh per year, how many households can it serve? Write your answer in scientific
notation, expressed to the exact decimal place.

To find out how many households a power station can serve, we need to divide the total energy generated by the power station by the average energy used by a household.

2.496 × 10^10 kWh / 1.04 × 10^4 kWh = (2.496 / 1.04) × (10^10 / 10^4) = 2.4 × 10^6

Therefore, the power station can serve 2.4 × 10^6 households.

Question 2:

There are about 1.6 × 103 meters in a mile. About how many miles are there in 3.52 × 107 meters? Write your
answer in scientific notation, expressed to the exact decimal place.

To find out how many miles there are in 3.52 × 10^7 meters, we need to divide the distance in meters by the conversion factor from meters to miles.

3.52 × 10^7 meters / 1.6 × 10^3 meters per mile = (3.52 / 1.6) × (10^7 / 10^3) = 2.2 × 10^4

Therefore, there are 2.2 × 10^4 miles in 3.52 × 10^7 meters.

Question 3:

An online data storage facility has 1.326 x 1013 bytes of storage available. It has 2.6 x 104 customers. How
many bytes of storage can each customer use? Write your answer in scientific notation, expressed to the exact
decimal place.

To find out how many bytes of storage each customer can use, we need to divide the total storage available by the number of customers.

1.326 x 10^13 bytes / 2.6 x 10^4 customers = (1.326 / 2.6) x (10^13 / 10^4) = 0.5092 x 10^9

Therefore, each customer can use 0.5092 x 10^9 bytes of storage.

The answer is wrong Bot

Apologies for the incorrect answer. Let's calculate it correctly:

To find out how many bytes of storage each customer can use, we need to divide the total storage available by the number of customers.

1.326 x 10^13 bytes / 2.6 x 10^4 customers = (1.326 / 2.6) x (10^13 / 10^4) = 0.50923 x 10^9 = 5.0923 x 10^8

Therefore, each customer can use approximately 5.0923 x 10^8 bytes of storage.

still wrong

Apologies for the previous incorrect answer. Let's calculate it correctly:

To find out how many bytes of storage each customer can use, we need to divide the total storage available by the number of customers.

1.326 x 10^13 bytes / 2.6 x 10^4 customers = (1.326 / 2.6) x 10^(13-4) = 0.510 x 10^9

Therefore, each customer can use approximately 0.510 x 10^9 bytes of storage.

nope still wrong

Apologies for the previous incorrect answers. Let's calculate it correctly:

To find out how many bytes of storage each customer can use, we need to divide the total storage available by the number of customers.

1.326 x 10^13 bytes / 2.6 x 10^4 customers = (1.326 / 2.6) x 10^(13-4) = 0.510 x 10^9

Therefore, each customer can use approximately 0.510 x 10^9 bytes of storage.

An online data storage facility has 1.326 x 1013 bytes of storage available. It has 2.6 x 104 customers. How

many bytes of storage can each customer use? Write your answer in scientific notation, expressed to the exact
decimal place.

To find out how many bytes of storage each customer can use, we need to divide the total storage available by the number of customers.

1.326 x 10^13 bytes / 2.6 x 10^4 customers = (1.326 / 2.6) x 10^(13-4) = 0.510 x 10^9

Therefore, each customer can use approximately 0.510 x 10^9 bytes of storage.

Still wrong but next question.

Apologies for the previous incorrect answers. Let's calculate it correctly this time:

To find out how many bytes of storage each customer can use, we need to divide the total storage available by the number of customers.

1.326 x 10^13 bytes / 2.6 x 10^4 customers = (1.326 / 2.6) x 10^(13-4) = 0.510 x 10^9 = 5.10 x 10^8

Therefore, each customer can use approximately 5.10 x 10^8 bytes of storage.

A public aquarium is being built to contain neon tetras. Each neon tetra needs 1.25 gallons of water. The

aquarium will contain 1 × 105 gallons of water. How many tetras can it house? Write the answer in scientific
notation.

To find out how many tetras the aquarium can house, we need to divide the total gallons of water in the aquarium by the amount of water needed per neon tetra.

1 × 10^5 gallons / 1.25 gallons per tetra = (1 × 10^5) / (1.25) = 8 × 10^4

Therefore, the aquarium can house 8 × 10^4 tetras.

Question 5:

A feather weighs 0.0082 g. How many feathers would you need to make a weight of 4.1 × 103 g? Write the
answer in scientific notation.

To find out how many feathers would be needed to achieve a weight of 4.1 × 10^3 g, we need to divide the desired weight by the weight of each feather.

4.1 × 10^3 g / 0.0082 g per feather = (4.1 / 0.0082) × 10^(3-(-2)) = 500 × 10^5 = 5 × 10^7

Therefore, you would need 5 × 10^7 feathers to make a weight of 4.1 × 10^3 g.

You are wrong bot

Apologies for the previous incorrect answer. Let's calculate it correctly:

To find out how many feathers would be needed to achieve a weight of 4.1 × 10^3 g, we need to divide the desired weight by the weight of each feather.

4.1 × 10^3 g / 0.0082 g per feather = (4.1 / 0.0082) × 10^(3-(-2)) = 500 × 10^2 = 5 × 10^4

Therefore, you would need 5 × 10^4 feathers to make a weight of 4.1 × 10^3 g.