An average American household uses about 1.04×10^4 kWh (kilowatt hours) of electricity a year. If a power station generates 2.496×10^10 kWh per year, how many households can it serve? Write your answer in scientific notation, expressed to the exact decimal place.
To find out how many miles there are in 3.52×10^7 meters, we need to divide the number of meters by the conversion factor from meters to miles.
The conversion factor is 1.6×10^3 meters per mile.
The number of miles can be calculated by:
(3.52×10^7 meters) ÷ (1.6×10^3 meters per mile)
To divide these numbers in scientific notation, we divide the coefficients and subtract the exponents:
(3.52 ÷ 1.6) × 10^(7 - 3)
= 2.2 × 10^(4)
Therefore, there are 2.2 × 10^4 miles in 3.52×10^7 meters.
To find out how many miles there are in 3.52×10^7 meters, we need to divide the number of meters by the conversion factor from meters to miles.
The conversion factor is 1 mile / 1.6×10^3 meters.
The number of miles can be calculated by:
(3.52×10^7 meters) ÷ (1.6×10^3 meters per mile)
To divide these numbers in scientific notation, we divide the coefficients and subtract the exponents:
(3.52 ÷ 1.6) × 10^(7 - 3)
= 2.2 × 10^(4)
Therefore, there are 2.2 × 10^4 miles in 3.52×10^7 meters.
To find out how many neon tetras the aquarium can house, we need to divide the total gallons of water in the aquarium by the amount of water needed per neon tetra.
The aquarium contains 1×10^5 gallons of water and each neon tetra needs 1.25 gallons of water.
The number of tetras the aquarium can house is given by:
(1×10^5 gallons) ÷ (1.25 gallons per tetra)
To divide these numbers in scientific notation, we divide the coefficients and subtract the exponents:
(1 ÷ 1.25) × 10^(5 - 0)
= 0.8 × 10^5
Since the coefficient is less than 1, we can rewrite it as 8 multiplied by 10 raised to the power of (5 - 1):
= 8 × 10^4
Therefore, the aquarium can house 8 × 10^4 neon tetras.
For an easier way to review answers
1. 2.4 x 10^6
2. 2.2 x 10^4
3. 5.1 x 10^8
4. 8 x 10^4
5. 5 x 10^5
To find out how many households a power station can serve, we need to divide the total amount of electricity generated by the power station by the average amount of electricity used by a household.
The power station generates 2.496×10^10 kWh per year, and each household uses 1.04×10^4 kWh per year.
The number of households that can be served is given by:
2.496×10^10 kWh ÷ 1.04×10^4 kWh
To divide these numbers in scientific notation, we subtract the exponents and divide the coefficients:
(2.496 ÷ 1.04) × 10^(10 - 4)
= 2.4 × 10^(6)
Therefore, the power station can serve 2.4 × 10^6 households.
To find out how many bytes of storage each customer can use, we need to divide the total storage available by the number of customers.
The data storage facility has 1.326×10^13 bytes of storage and 2.6×10^4 customers.
The number of bytes each customer can use is given by:
(1.326×10^13 bytes) ÷ (2.6×10^4 customers)
To divide these numbers in scientific notation, we divide the coefficients and subtract the exponents:
(1.326 ÷ 2.6) × 10^(13 - 4)
= 0.51 × 10^(9)
Since the coefficient is less than 1, we can rewrite it as 5.1 multiplied by 10 raised to the power of (9 - 1):
= 5.1 × 10^8
Therefore, each customer can use 5.1 × 10^8 bytes of storage.