A side of the triangle below has been extended to form an exterior angle of 132°. Find the value of x.
[asy]
size(100);
pair C, B, A;
A = (0,0);
C = (5,0);
B = (1.3, 2.6);
draw(A--B--C--cycle);
label("$x^\circ$", (0.5,0.2), NE);
label("$x^\circ$", (4.5,0.2), NW);
label("$132^\circ$", (0.65, 0.9), NW);
[/asy]
The sum of the angles in a triangle is $180^\circ$, so we have $x + x + 132 = 180$. Simplifying the left side gives $2x + 132 = 180$, so $2x = 48$. Dividing both sides by 2 gives $x=\boxed{24}$.