x->8
When x approaches 8, it means that the value of x gets closer and closer to 8, but never reaches exactly 8. This is denoted using limits in calculus as "lim x -> 8".
The expression "x->8" is not clear. It appears to be missing an equation or context for me to provide a meaningful answer. Please provide more information or rephrase your question.
solve x+8>10
To solve the inequality x + 8 > 10, we can start by subtracting 8 from both sides of the inequality:
x + 8 - 8 > 10 - 8
Simplifying further, we get:
x > 2
Therefore, the solution to the inequality is x > 2. This means that any value of x greater than 2 will make the inequality true.
solve x-1/3<1/2
To solve the inequality x - 1/3 < 1/2, we can start by adding 1/3 to both sides of the inequality:
x - 1/3 + 1/3 < 1/2 + 1/3
Simplifying further, we get:
x < 5/6
Therefore, the solution to the inequality is x < 5/6. This means that any value of x less than 5/6 will make the inequality true.
x+14<25
To solve the inequality x + 14 < 25, we can start by subtracting 14 from both sides of the inequality:
x + 14 - 14 < 25 - 14
Simplifying further, we get:
x < 11
Therefore, the solution to the inequality is x < 11. This means that any value of x less than 11 will make the inequality true.
x-8>5
To solve the inequality x - 8 > 5, we can start by adding 8 to both sides of the inequality:
x - 8 + 8 > 5 + 8
Simplifying further, we get:
x > 13
Therefore, the solution to the inequality is x > 13. This means that any value of x greater than 13 will make the inequality true.