A 20 kg dog has 250 J of kinetic energy as it chases after a cat. The dog’s velocity is __________. (1 point)
Responses
25 m/s
25 m/s
12.5 m/s
12.5 m/s
5 m/s
5 m/s
250 m/s
To solve for the velocity, we can use the formula for kinetic energy:
KE = 1/2 * m * v^2
Given that the dog has 250 J of kinetic energy and weighs 20 kg, we can rearrange the formula to solve for v:
250 = 1/2 * 20 * v^2
Simplifying this equation, we have:
250 = 10 * v^2
Dividing both sides of the equation by 10:
25 = v^2
Taking the square root of both sides:
v = √25
v = 5 m/s
Therefore, the dog's velocity is 5 m/s.
To find the velocity of the dog, we can use the equation for kinetic energy:
Kinetic energy = (1/2) * mass * velocity^2
Given that the dog has a mass of 20 kg and kinetic energy of 250 J, we can rearrange the equation to solve for velocity:
250 J = (1/2) * 20 kg * velocity^2
Dividing both sides by (1/2) * 20 kg:
250 J / (1/2) * 20 kg = velocity^2
Simplifying the equation:
250 J / 10 kg = velocity^2
25 m/s = velocity^2
Taking the square root of both sides:
velocity = √(25 m/s)
velocity = 5 m/s
Therefore, the dog's velocity is 5 m/s.