Put on a graphic number line X +0.5. >_ 0.5

Here is a graphical representation of the number line with X + 0.5 > 0.5:

```
-2 -1.5 -1 -0.5 0 0.5 1 1.5 2
---------------------------------------------------------------------------------------------
|--------------------|------------------> X
False True
```

In this number line, there is a point labeled "0.5" as the reference point. The inequality states that X + 0.5 is greater than 0.5. The point "X" indicates the values that satisfy this inequality. As shown in the graphic, any value of X to the right of the point "0.5" satisfies the inequality.

To put the number X + 0.5 on a graphic number line, we can follow these steps:

1. Draw a horizontal line and mark a point at the center. This represents zero.

2. To the right of the zero, mark a point at 0.5. Label it as 0.5. This represents the point on the number line.

3. To show X + 0.5 on the number line, mark another point to the right of 0.5, representing the value of X. Label it as X.

4. Connect the points 0.5 and X with a line segment.

The resulting graphic number line would show the point X + 0.5 to the right of 0.5.

To graph the expression "X + 0.5 > 0.5" on a number line, we need to follow a few steps:

Step 1: Set up the number line.
Draw a horizontal line and label it with numbers. Make sure to include the value 0.5 on the line.

Step 2: Mark the solutions.
Since the equation has an inequality symbol (">"), we are looking for values of X that make the expression true. In this case, any value of X greater than 0 on the number line will satisfy the inequality "X + 0.5 > 0.5".

Step 3: Shade the solution region.
Shade the region to the right of the number 0 on the number line. This indicates all the acceptable values of X that satisfy the inequality.

Here's a graphical representation of the number line with the solution:

-2 -1 0 1 2 3
---------------------------------------
|-------------------------
The shaded region indicates the values of X that satisfy the inequality "X + 0.5 > 0.5". In this case, any value of X greater than 0 will make the expression true.