A small pool holds 950 gallons of water. If a pump removes 300 gallons of water in 6 minutes, what is the change in the amount of water in gallons in 1 minute.
The change in the amount of water in gallons in 1 minute is 300 gallons / 6 minutes = <<300/6=50>>50 gallons/minute. Answer: \boxed{50}.
To find the change in the amount of water in gallons per minute, you need to determine the rate at which the pump removes water.
First, calculate the rate at which the pump removes water by dividing the total amount of water removed by the time it takes: 300 gallons ÷ 6 minutes = 50 gallons per minute.
Therefore, the pump removes water at a rate of 50 gallons per minute. Since the question asks for the change in the amount of water, you need to subtract this rate from the total amount of water in the pool.
To calculate the change in the amount of water in 1 minute, subtract the rate of water removal (50 gallons/minute) from the total amount of water (950 gallons): 950 gallons - 50 gallons = 900 gallons.
Hence, the change in the amount of water in 1 minute is 900 gallons.
To find the change in the amount of water in 1 minute, we need to determine how much water the pump removes in 1 minute.
We can start by finding the rate at which the pump removes water per minute. To do this, divide the amount of water removed (300 gallons) by the time taken (6 minutes):
Rate = Amount of water removed / Time taken
Rate = 300 gallons / 6 minutes
Rate = 50 gallons per minute
Therefore, the pump removes 50 gallons of water in 1 minute.
Next, we need to calculate the change in the amount of water in 1 minute. Since the pump removes water, the change will be negative. Subtracting the rate at which water is being removed from the total amount of water in the pool:
Change in water = - (Rate at which water is removed)
Change in water = - 50 gallons per minute
Therefore, the change in the amount of water in 1 minute is -50 gallons.