Use the chemical reaction to answer the question c a c o 3 arrow CO2 + CAO a scientist heats 30 g of calcium carbonate CaCO3 in the chemical reaction show what is the total mass of the products 15 g 60 g 30 g or 10 g
The balanced chemical equation for the reaction is:
CaCO3 → CO2 + CaO
According to the law of conservation of mass, the total mass of the reactants should be equal to the total mass of the products.
Given that the scientist heats 30 g of calcium carbonate (CaCO3), the total mass of the products can be determined by looking at the coefficients in the balanced equation.
From the equation, it can be seen that 1 mole of CaCO3 will produce 1 mole of CO2 and 1 mole of CaO. The molar mass of CaCO3 is 100.09 g/mol.
So, 1 mole of CaCO3 has a mass of 100.09 g.
Since the molar ratio of CaCO3 to CO2 is 1:1, the mass of CO2 produced will also be 100.09 g.
Similarly, the molar ratio of CaCO3 to CaO is 1:1, so the mass of CaO produced will also be 100.09 g.
Therefore, the total mass of the products (CO2 + CaO) will be 100.09 g + 100.09 g = 200.18 g.
Thus, the correct answer is 200.18 g.
The balanced chemical equation for the reaction is:
CaCO3 → CO2 + CaO
From the equation, we can see that 1 mole of CaCO3 will produce 1 mole of CO2 and 1 mole of CaO.
To determine the total mass of the products, we need to calculate the molar mass of each compound involved.
The molar mass of CaCO3 can be calculated as follows:
(Ca) 40.08 g/mol + (C) 12.01 g/mol + (3 * O) 3 * 16.00 g/mol = 100.09 g/mol
Since the molar mass of CaCO3 is 100.09 g/mol, we can calculate the number of moles present in 30 g of CaCO3 as:
Number of moles = mass / molar mass = 30 g / 100.09 g/mol = 0.2999 mol (approximately)
According to the balanced chemical equation, 1 mole of CaCO3 produces 1 mole of CO2 and 1 mole of CaO. Therefore, the total moles of products formed will be the same.
The molar mass of CO2 can be calculated as follows:
(C) 12.01 g/mol + (2 * O) 2 * 16.00 g/mol = 44.01 g/mol
The molar mass of CaO can be calculated as follows:
(Ca) 40.08 g/mol + (O) 16.00 g/mol = 56.08 g/mol
Now, we can calculate the mass of the products:
Mass of CO2 = Number of moles * Molar mass of CO2 = 0.2999 mol * 44.01 g/mol = 13.20 g (approximately)
Mass of CaO = Number of moles * Molar mass of CaO = 0.2999 mol *56.08 g/mol= 16.81 g (approximately)
Therefore, the total mass of the products is:
Mass of CO2 + Mass of CaO = 13.20 g + 16.81 g = 30.01 g (approximately)
So, the total mass of the products in the reaction is approximately 30 g.
To determine the total mass of the products in the chemical reaction, we need to understand the concept of conservation of mass. According to this principle, mass is neither created nor destroyed in a chemical reaction. Thus, the total mass of the products should be equal to the total mass of the reactants.
In the given chemical reaction: CaCO3 → CO2 + CaO
The molar mass of CaCO3 is calculated as follows:
1 atom of Ca (40.08 g/mol) + 1 atom of C (12.01 g/mol) + 3 atoms of O (16.00 g/mol) = 100.09 g/mol
Since we are given that 30 g of CaCO3 is heated, we can calculate the number of moles of CaCO3:
30 g / 100.09 g/mol = 0.29989 mol
Looking at the balanced equation, we can see that 1 mole of CaCO3 produces 1 mole of CO2 and 1 mole of CaO. Therefore, the total moles of CO2 and CaO produced will also be 0.29989 mol each.
Now, we can calculate the mass of the products:
Mass of CO2 = 0.29989 mol × (12.01 g/mol) = 3.6002889 g ≈ 3.6 g
Mass of CaO = 0.29989 mol × (56.08 g/mol) = 16.8327792 g ≈ 16.8 g
Therefore, the total mass of the products is approximately 3.6 g + 16.8 g = 20.4 g.
Among the given options, the closest answer to 20.4 g is 30 g. However, it should be noted that the correct answer based on the calculations is not among the provided options.