For which equation is the order of steps to first divide both sides by 6 and then to add 8 to both sides?(1 point)
Responses

8(x − 6) = 48
8 left parenthesis x minus 6 right parenthesis equals 48

6(x − 8) = 48
6 left parenthesis x minus 8 right parenthesis equals 48

6x − 8 = 48
6 x minus 8 equals 48

6(x + 8) = 48
6 left parenthesis x plus 8 right parenthesis equals 48
The equation for which the order of steps is to first divide both sides by 6 and then add 8 to both sides is 6x - 8 = 48.
To determine which equation requires dividing both sides by 6 first and then adding 8 to both sides, we need to analyze the equations and identify the steps that need to be taken in order to isolate the variable.
Let's look at each equation:
1) 8(x - 6) = 48
2) 6(x - 8) = 48
3) 6x - 8 = 48
4) 6(x + 8) = 48
In this case, the equation that requires dividing both sides by 6 first and then adding 8 to both sides is the equation (3). Here's how the steps would unfold:
1) Start with 6x - 8 = 48
2) Divide both sides by 6: (6x - 8)/6 = 48/6
3) Simplify: x - 8/6 = 8
4) Add 8 to both sides: x - 8/6 + 8 = 8 + 8
5) Simplify: x - 8/6 + 48/6 = 16/6
6) Combine like terms: x - 4/3 = 8/3
So, the equation where we first need to divide both sides by 6 and then add 8 to both sides is 6x - 8 = 48.