How many molecules of ethane are present in 0.862 g of c2h6
To find the number of molecules of ethane (C2H6) present in 0.862 g, we need to use the concept of moles and Avogadro's number.
1. Calculate the molar mass of ethane (C2H6):
- 2 carbon atoms (C) with a molar mass of 12.01 g/mol each = 24.02 g/mol
- 6 hydrogen atoms (H) with a molar mass of 1.01 g/mol each = 6.06 g/mol
- Total molar mass of ethane (C2H6) = 24.02 g/mol + 6.06 g/mol = 30.08 g/mol
2. Calculate the number of moles of ethane:
- Moles = Mass / Molar mass
- Moles = 0.862 g / 30.08 g/mol ≈ 0.0286 mol
3. Use Avogadro's number to find the number of molecules of ethane:
- Avogadro's number is approximately 6.022 x 10^23 molecules/mol
- Number of molecules = Moles x Avogadro's number
- Number of molecules = 0.0286 mol x 6.022 x 10^23 molecules/mol ≈ 1.72 x 10^22 molecules
Therefore, there are approximately 1.72 x 10^22 molecules of ethane (C2H6) present in 0.862 g.
To find the number of molecules of ethane (C2H6) present in 0.862 g, we need to follow a step-by-step approach using the concept of molar mass and Avogadro's number.
1. Determine the molar mass of ethane (C2H6).
- The molar mass is the sum of the atomic masses of all the atoms in the molecule.
- Carbon (C) has an atomic mass of 12.01 g/mol, and hydrogen (H) has an atomic mass of 1.01 g/mol.
- Since there are 2 carbon atoms and 6 hydrogen atoms in ethane, the molar mass is:
Molar mass of ethane = (2 × atomic mass of carbon) + (6 × atomic mass of hydrogen)
= (2 × 12.01 g/mol) + (6 × 1.01 g/mol)
= 30.08 g/mol
2. Calculate the number of moles of ethane.
- We can use the formula: Moles = Mass / Molar mass
- Substituting the given mass (0.862 g) and the molar mass of ethane (30.08 g/mol):
Moles of ethane = 0.862 g / 30.08 g/mol
≈ 0.0286 mol
3. Apply Avogadro's number to convert moles to molecules.
- Avogadro's number (Na) is approximately 6.022 × 10^23 molecules/mol.
Number of ethane molecules = Moles of ethane × Avogadro's number
= 0.0286 mol × (6.022 × 10^23 molecules/mol)
≈ 1.72 × 10^22 molecules
Therefore, approximately 1.72 × 10^22 molecules of ethane are present in 0.862 g of C2H6.
To calculate the number of molecules of ethane (C2H6) present in 0.862 g, you first need to convert the mass into moles using the molar mass of ethane.
1. Find the molar mass of ethane (C2H6):
- The molar mass of carbon (C) is 12.01 g/mol.
- The molar mass of hydrogen (H) is 1.01 g/mol.
- Ethane has 2 carbon atoms and 6 hydrogen atoms.
- Molar mass of ethane = (2 * 12.01 g/mol) + (6 * 1.01 g/mol) = 30.07 g/mol.
2. Calculate the number of moles of ethane:
- Moles = Mass / Molar mass.
- Moles = 0.862 g / 30.07 g/mol ≈ 0.0287 mol.
3. Determine Avogadro's number:
- Avogadro's number (represented as "NA") is 6.022 x 10^23 molecules/mol.
4. Find the number of molecules:
- Number of molecules = Moles * Avogadro's number.
- Number of molecules = 0.0287 mol * 6.022 x 10^23 molecules/mol ≈ 1.73 x 10^22 molecules.
Therefore, there are approximately 1.73 x 10^22 molecules of ethane present in 0.862 g of C2H6.